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Modifying pixels using for loops

Modifying pixels using for loops#

We can access the color information of certain columns of images in a similar way. We still have the 3X4 image saved as a 2D list our_image.

../../../_images/rows.png

The RGB values of each pixel is as follows:

(0,0,0)   (0,80,0)   (0,160,0)   (0,240,0)
(120,0,0) (120,80,0) (120,160,0) (120,240,0)
(240,0,0) (240,80,0) (240,160,0) (240,240,0)

In the previous slide, we managed to change one pixel from (0,0,0) to (0,0,225). But, what if we want to make every pixel at the bottom row to have B component as 225? Let’s first bring back the code that accessed the bottom row.

for column in range(4):
    print(our_image[2][column])

Now, instead of printing each pixel, let’s save it to a temporary variable temp_pixel.

for column in range(4):
    temp_pixel = our_image[2][column]

Then for each iteration, temp_pixel is assigned with a tuple that has the color information of the corresponding pixel. To be specific,

  • column is 0 at the initial iteration

    • temp_pixel is (240,0,0)

  • column is 1 at the next iteration

    • temp_pixel is (240,80,0)

  • column is 2 at the next iteration

    • temp_pixel is (240,160,0)

  • column is 3 at the next iteration

    • temp_pixel is (240,240,0)

For every iteration, temp_pixel[0], temp_pixel[1], temp_pixel[2] indicate the R component, G component, B component, respectively. Therefore, we can create a new tuple (temp_pixel[0], temp_pixel[1], 255) for each iteration and assign the newly created tuple back to the pixel our_image[2][column].

for column in range(4):
    temp_pixel = our_image[2][column]
    our_image[2][column] = (temp_pixel[0], temp_pixel[1], 255)

As a result, the RGB components become:

(0,0,0)     (0,80,0)     (0,160,0)     (0,240,0)
(120,0,0)   (120,80,0)   (120,160,0)   (120,240,0)
(240,0,255) (240,80,255) (240,160,255) (240,240,255)